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538.把二叉搜索树转换为累加树
题解
js
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {TreeNode}
*/
var convertBST = function (root) {
let pre = 0;
function fn(root) {
if (!root) return;
fn(root.right);
if (pre) {
// 和当前节点累加
root.val += pre;
}
// 记录前一个值
pre = root.val;
fn(root.left);
}
fn(root);
return root;
};
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {TreeNode}
*/
var convertBST = function (root) {
let pre = 0;
function fn(root) {
if (!root) return;
fn(root.right);
if (pre) {
// 和当前节点累加
root.val += pre;
}
// 记录前一个值
pre = root.val;
fn(root.left);
}
fn(root);
return root;
};