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530.二叉搜索树的最小绝对差
题解
js
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var getMinimumDifference = function (root) {
var pre;
var min = Number.MAX_VALUE;
function dfs(root) {
if (!root) return;
dfs(root.left); // 左
if (pre != null) {
// 当前值 - 上次的值 求最小差
min = Math.min(min, root.val - pre);
}
pre = root.val; // 记录上一次的值
dfs(root.right); // 右
}
dfs(root);
return min;
};
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number}
*/
var getMinimumDifference = function (root) {
var pre;
var min = Number.MAX_VALUE;
function dfs(root) {
if (!root) return;
dfs(root.left); // 左
if (pre != null) {
// 当前值 - 上次的值 求最小差
min = Math.min(min, root.val - pre);
}
pre = root.val; // 记录上一次的值
dfs(root.right); // 右
}
dfs(root);
return min;
};