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236.二叉树的最近公共祖先
题解
js
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @param {TreeNode} p
* @param {TreeNode} q
* @return {TreeNode}
*/
var lowestCommonAncestor = function (root, p, q) {
if (!root || p === root || q === root) return root;
const leftNode = lowestCommonAncestor(root.left, p, q);
const rightNode = lowestCommonAncestor(root.right, p, q);
// 如果左子树找到了节点,右子树也找到了节点,当前节点就是祖先节点
if (leftNode && rightNode) return root;
return leftNode || rightNode;
};
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @param {TreeNode} p
* @param {TreeNode} q
* @return {TreeNode}
*/
var lowestCommonAncestor = function (root, p, q) {
if (!root || p === root || q === root) return root;
const leftNode = lowestCommonAncestor(root.left, p, q);
const rightNode = lowestCommonAncestor(root.right, p, q);
// 如果左子树找到了节点,右子树也找到了节点,当前节点就是祖先节点
if (leftNode && rightNode) return root;
return leftNode || rightNode;
};